A common test point is the origin, (0, 0). Write an inequality that describes all points in the half-plane right of the y-axis. For example, all of the solutions to are shaded in the graph below.
Which Statements Are True About The Linear Inequality Y 3/4.2 Ko
Provide step-by-step explanations. Solutions to linear inequalities are a shaded half-plane, bounded by a solid line or a dashed line. The boundary is a basic parabola shifted 3 units up. Select two values, and plug them into the equation to find the corresponding values. In this example, notice that the solution set consists of all the ordered pairs below the boundary line. B The graph of is a dashed line. Which statements are true about the linear inequality y 3/4.2.4. The slope-intercept form is, where is the slope and is the y-intercept. The boundary of the region is a parabola, shown as a dashed curve on the graph, and is not part of the solution set. Still have questions?
Which Statements Are True About The Linear Inequality Y 3/4.2.3
Graph the line using the slope and the y-intercept, or the points. Begin by drawing a dashed parabolic boundary because of the strict inequality. Unlimited access to all gallery answers. The graph of the solution set to a linear inequality is always a region. This indicates that any ordered pair in the shaded region, including the boundary line, will satisfy the inequality. These ideas and techniques extend to nonlinear inequalities with two variables. In this case, shade the region that does not contain the test point. E The graph intercepts the y-axis at. Feedback from students. Which statements are true about the linear inequality y 3/4.2.3. Crop a question and search for answer.
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This boundary is either included in the solution or not, depending on the given inequality. Any line can be graphed using two points. Step 2: Test a point that is not on the boundary. D One solution to the inequality is. Let x represent the number of products sold at $8 and let y represent the number of products sold at $12. We solved the question! Because The solution is the area above the dashed line. Graph the boundary first and then test a point to determine which region contains the solutions. Now consider the following graphs with the same boundary: Greater Than (Above). Which statements are true about the linear inequality y 3/4.2.5. Next, test a point; this helps decide which region to shade. However, from the graph we expect the ordered pair (−1, 4) to be a solution. Does the answer help you?
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We know that a linear equation with two variables has infinitely many ordered pair solutions that form a line when graphed. Here the boundary is defined by the line Since the inequality is inclusive, we graph the boundary using a solid line. You are encouraged to test points in and out of each solution set that is graphed above. Which statements are true about the linear inequality y >3/4 x – 2? Check all that apply. -The - Brainly.com. The inequality is satisfied. We can see that the slope is and the y-intercept is (0, 1). Following are graphs of solutions sets of inequalities with inclusive parabolic boundaries.
Which Statements Are True About The Linear Inequality Y 3/4.2.0
Grade 12 · 2021-06-23. Because the slope of the line is equal to. To see that this is the case, choose a few test points A point not on the boundary of the linear inequality used as a means to determine in which half-plane the solutions lie. Slope: y-intercept: Step 3. In this case, graph the boundary line using intercepts. To find the x-intercept, set y = 0. Answer: is a solution.
Which Statements Are True About The Linear Inequality Y 3/4.2.4
Shade with caution; sometimes the boundary is given in standard form, in which case these rules do not apply. Enjoy live Q&A or pic answer. Create a table of the and values. Non-Inclusive Boundary.
The slope of the line is the value of, and the y-intercept is the value of. It is graphed using a solid curve because of the inclusive inequality. Since the test point is in the solution set, shade the half of the plane that contains it. The statement is True. Because of the strict inequality, we will graph the boundary using a dashed line. Furthermore, we expect that ordered pairs that are not in the shaded region, such as (−3, 2), will not satisfy the inequality. And substitute them into the inequality. Gauthmath helper for Chrome.
To find the y-intercept, set x = 0. x-intercept: (−5, 0). Solve for y and you see that the shading is correct. If, then shade below the line. Gauth Tutor Solution. Rewrite in slope-intercept form. A linear inequality with two variables An inequality relating linear expressions with two variables. Answer: Consider the problem of shading above or below the boundary line when the inequality is in slope-intercept form. A The slope of the line is. How many of each product must be sold so that revenues are at least $2, 400? It is the "or equal to" part of the inclusive inequality that makes the ordered pair part of the solution set. In slope-intercept form, you can see that the region below the boundary line should be shaded. The boundary is a basic parabola shifted 2 units to the left and 1 unit down. Step 1: Graph the boundary. Also, we can see that ordered pairs outside the shaded region do not solve the linear inequality.
In the previous example, the line was part of the solution set because of the "or equal to" part of the inclusive inequality If given a strict inequality, we would then use a dashed line to indicate that those points are not included in the solution set. Find the values of and using the form. C The area below the line is shaded. See the attached figure. Is the ordered pair a solution to the given inequality? Solution: Substitute the x- and y-values into the equation and see if a true statement is obtained. This may seem counterintuitive because the original inequality involved "greater than" This illustrates that it is a best practice to actually test a point. Write a linear inequality in terms of x and y and sketch the graph of all possible solutions. Ask a live tutor for help now. Check the full answer on App Gauthmath.
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